(06-10-2020, 12:09 PM)michaeltex Wrote:Win percentage if they finish with a different final amount of games, and then normal tiebreakers.(06-10-2020, 07:34 AM)MrGoat Wrote:What happens if there are two teams tied for 9th but within 4 of 8th? Normal tie breakers?(06-09-2020, 09:21 AM)omahen Wrote:(06-09-2020, 05:54 AM)khaled1987 Wrote: Don't the 9th seed need a 3 game difference between 8th seed or something like that?
4 game difference, SA is 5 games behind. So in theory totally reachable
Actually SA is only 4 games behind Memphis. 32-33 is 5 more wins but 3 less losses than 27-36 which averages out to 4. Memphis is going to need to gain extra distance on SA, Portland, New Orleans, and Sacramento to avoid a play in
I know it's unlikely, but this season is already weird enough, why not a little more?
For example. The Kings, Blazers, and Pelicans are all 3 and a half behind Memphis. Say the Kings, Grizzlies, Blazers, and Pelican all go 4-4. The Blazers get the play in because 33-41 would be a slightly better win percentage than the 32-40 the Kings and Pelicans would have even though they would all be the same amount of games down.
But if the Kings and Pelicans finish with the same record tied for 9th then it would come down to the normal tiebreakers to determine 9 vs. 10. Head to head, division winner, better division record, better conference record, etc. This would only be the case with the Kings and Pelicans, everyone else would come down to winning percentage because they have all played a different amount of games. If the Kings and Pelicans aren't scheduled to play each other again the tiebreaker would go to New Orleans, if they do then it would go to Sacramento if they win that game. This is because the Pelicans are 1-0 against the Kings but have an abysmal in division record